2^(2x)=32^10

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Solution for 2^(2x)=32^10 equation: 



2^(2x)=32^10

We move all terms to the left:

2^(2x)-(32^10)=0

We add all the numbers together, and all the variables

2^2x-1125899906842624=0

We move all terms containing x to the left, all other terms to the right

2^2x=1125899906842624

x=1125899906842624/1

x=1125899906842624

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